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JEE Main 2021 (24 Feb, Shift 1) · Junction Transistor

Junction Transistor question from JEE Main 2021 (24 Feb, Shift 1)

Q65JEE Main 2021 · 24 FEB · SHIFT 1Easy

Junction Transistor

If an emitter current is changed by 4 mA, the collector current changes by 3.5 mA. The value of $\beta$ will be:

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Answer: (d)

$\Delta I_B = \Delta I_E - \Delta I_C = 4 - 3.5 = 0.5$ mA
$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{3.5}{0.5} = 7$
So the answer is (d) 7.

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