If ε₀ and μ₀ are the electric permittivity and magnetic permeability in a free space, ε and μ are the corresponding quantities in medium, the index of refraction of the medium is (a) √((ε₀ μ₀)/(ε μ)) (b) √((ε μ)/(ε₀ μ₀)) (c) √((ε₀ μ)/(ε μ₀)) (d) √((ε)/(ε₀))

Answer: (b). n = c/v with c = (1)/(√(ε₀μ₀)) and v = (1)/(√(εμ)). n = √((εμ)/(ε₀μ₀)). So the answer is (b).

If ε₀ and μ₀ are the electric permittivity and magnetic permeability… | NEET 1997 (AIPMT)

Q28NEET 1997 · AIPMTEasy

Speed of EM Waves in a Medium

If $\varepsilon_0$ and $\mu_0$ are the electric permittivity and magnetic permeability in a free space, $\varepsilon$ and $\mu$ are the corresponding quantities in medium, the index of refraction of the medium is

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Answer: (b)

$n = \dfrac{c}{v}$ with $c = \dfrac{1}{\sqrt{\varepsilon_0\mu_0}}$ and $v = \dfrac{1}{\sqrt{\varepsilon\mu}}$ .
$n = \sqrt{\dfrac{\varepsilon\mu}{\varepsilon_0\mu_0}}$ .
So the answer is (b).

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Speed of EM Waves in a Medium question from NEET 1997 (AIPMT)

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