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MHT CET 2024 (3 May, Shift 1) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2024 (3 May, Shift 1)

Q22MHT CET 2024 · 3 MAY · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series

If ' $\lambda_1$ ' and ' $\lambda_2$ ' are the wavelengths of the first line of the Lyman and Paschen series respectively, then $\lambda_2 : \lambda_1$ is

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Answer: (d)

Lyman first line: $\lambda_1 = \frac{4}{3R}$ .
Paschen first line: $\frac{1}{\lambda_2} = R\left(\frac{1}{9} - \frac{1}{16}\right) = \frac{7R}{144}$ , so $\lambda_2 = \frac{144}{7R}$ .
$\frac{\lambda_2}{\lambda_1} = \frac{144}{7} \times \frac{3}{4} = \frac{108}{7}$ .
So the answer is (d) $108 : 7$ .

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