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JEE Main 2025 (22 Jan, Shift 1) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (22 Jan, Shift 1)

Q14JEE Main 2025 · 22 JAN · SHIFT 1Easy

Units & Dimensions

If BB is magnetic field and μ0\mu_0 is permeability of free space, then the dimensions of (B/μ0)(B/\mu_0) is

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Answer: (b)

  1. B/μ0=HB/\mu_0 = H, the magnetising field, measured in A/m\mathrm{A/m} (from B=μ0nIB = \mu_0 nI, nn = turns per metre).
  2. [B/μ0]=[nI]=L−1A[B/\mu_0] = [nI] = \mathrm{L^{-1}A}
  3. So the answer is (b) L−1A\mathrm{L^{-1}A}.
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