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JEE Main 2021 (26 Feb, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2021 (26 Feb, Shift 2)

Q58JEE Main 2021 · 26 FEB · SHIFT 2Easy

Units & Dimensions

If 'C' and 'V' represent capacitance and voltage respectively then what are the dimensions of λ\lambda where C/V = λ\lambda?

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Answer: (c)

  1. [V]=[W/q]=ML2T−3I−1[V] = [W/q] = \mathrm{ML^2T^{-3}I^{-1}}.
  2. [C]=[q/V]=IT/ML2T−3I−1=M−1L−2T4I2[C] = [q/V] = \mathrm{IT}/\mathrm{ML^2T^{-3}I^{-1}} = \mathrm{M^{-1}L^{-2}T^4I^2}.
  3. [λ]=[C/V]=M−2L−4T7I3[\lambda] = [C/V] = \mathrm{M^{-2}L^{-4}T^{7}I^{3}}
  4. So the answer is (c) [M−2L−4I3T7][M^{-2}L^{-4}I^3T^7].
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