If Cp and Cv are molar specific heats of an ideal gas at constant pressure and volume respectively and ' γ ' is Cp/Cv then Cp = ( R = universal gas constant) (a) (γ R)/(γ-1) (b) γ R (c) (1+γ)/(1-γ) (d) (R)/(γ-1)

Answer: (a). Mayer: Cp - Cv = R and Cv = (Cp)/(γ). Cp(1 - (1)/(γ)) = R ⇒ Cp = (γ R)/(γ-1) So the answer is (a) (γ R)/(γ-1).

If Cp and Cv are molar specific heats of an ideal gas at constant… | MHT CET 2024 (4 May, Shift 2)

Q15MHT CET 2024 · 4 MAY · SHIFT 2Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

If $C_p$ and $C_v$ are molar specific heats of an ideal gas at constant pressure and volume respectively and ' $\gamma$ ' is $C_p/C_v$ then $C_p =$ ( $R =$ universal gas constant)

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Answer: (a)

Mayer: $C_p - C_v = R$ and $C_v = \frac{C_p}{\gamma}$ .
$C_p\left(1 - \frac{1}{\gamma}\right) = R \Rightarrow C_p = \frac{\gamma R}{\gamma-1}$
So the answer is (a) $\frac{\gamma R}{\gamma-1}$ .

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2024 (4 May, Shift 2)

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