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MHT CET 2026 (18 Apr, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (18 Apr, Shift 2)

Q11MHT CET 2026 · 18 APR · SHIFT 2Easy

Self-Inductance & Energy

If current of 4 A produces magnetic flux of 3×10−33 \times 10^{-3} Wb through a coil of 400 turns, the energy stored in the coil will be

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Answer: (b)

  1. L=NϕI=400×3×10−34=0.3 HL = \dfrac{N\phi}{I} = \dfrac{400\times3\times10^{-3}}{4} = 0.3\text{ H}
  2. U=12LI2=12×0.3×16=2.4 JU = \tfrac12 L I^2 = \tfrac12\times0.3\times16 = 2.4\text{ J}
  3. So the answer is (b) 2.42.4 J.
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