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JEE Main 2025 (7 Apr, Shift 1) · Displacement Current, Maxwell's Equations & Production

Displacement Current, Maxwell's Equations & Production question from JEE Main 2025 (7 Apr, Shift 1)

Q4JEE Main 2025 · 7 APR · SHIFT 1Easy

Displacement Current, Maxwell's Equations & Production

If $\epsilon_0$ denotes the permittivity of free space and $\Phi_E$ is the flux of the electric field through the area bounded by the closed surface, then dimensions of $\left(\epsilon_0 \frac{d\phi_E}{dt}\right)$ are that of:

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Answer: (c)

Maxwell's displacement current is $I_d = \epsilon_0 \dfrac{d\phi_E}{dt}$ .
It enters Ampere-Maxwell law alongside the conduction current $I$ , so it has the same dimensions $[A]$ .
So the answer is (c) electric current.

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