If each diode has a forward bias resistance of 25 Ω in the below circuit, Which of the following options is correct: (a) (I₃)/(I₄) = 1 (b) (I₁)/(I₂) = 2 (c) (I₂)/(I₃) = 1 (d) (I₁)/(I₂) = 1

Answer: (b). D₁ and D₃ are forward biased; D₂ is reverse biased, so I₃ = 0. Each conducting branch: 25 + 125 = 150 Ω; two in parallel give 75 Ω. Total = 75 + 25 = 100 Ω. I₁ = 5/100 = 0.05 A, split equally: I₂ = I₄ = 0.025 A (I₁)/(I₂) = 2 So the answer is (b) (I₁)/(I₂) = 2.

If each diode has a forward bias resistance of 25 Ω in the below… | JEE Main 2023 (10 Apr, Shift 2)

Q59JEE Main 2023 · 10 APR · SHIFT 2Medium

P-N Junction Diode

If each diode has a forward bias resistance of $25\ \Omega$ in the below circuit,

Which of the following options is correct:

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Answer: (b)

$D_1$ and $D_3$ are forward biased; $D_2$ is reverse biased, so $I_3 = 0$ .
Each conducting branch: $25 + 125 = 150\ \Omega$ ; two in parallel give $75\ \Omega$ . Total $= 75 + 25 = 100\ \Omega$ .
$I_1 = \dfrac{5}{100} = 0.05$ A, split equally: $I_2 = I_4 = 0.025$ A
$\dfrac{I_1}{I_2} = 2$
So the answer is (b) $\frac{I_1}{I_2} = 2$ .

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