If F = 2i + j - k and r = 3i + 2j - 2k, then the scalar and vector products of F and r have the magnitudes respectively as (a) 10, 2 (b) 5, √(3) (c) 4, √(5) (d) 10, √(2)

Answer: (d). F · r = 6 + 2 + 2 = 10 F × r = i(-2 + 2) - j(-4 + 3) + k(4 - 3) = j + k |F × r| = √(2) So the answer is (d) 10, √(2).

If F = 2i + j - k and r = 3i + 2j - 2k, then the scalar and vector… | NEET 2022 (Phase 2)

Q9NEET 2022 · PHASE 2Easy

Vector (Cross) Product

If $\vec{F} = 2\hat{i} + \hat{j} - \hat{k}$ and $\vec{r} = 3\hat{i} + 2\hat{j} - 2\hat{k}$ , then the scalar and vector products of $\vec{F}$ and $\vec{r}$ have the magnitudes respectively as

Show answer and solution

Answer: (d)

$\vec{F} \cdot \vec{r} = 6 + 2 + 2 = 10$
$\vec{F} \times \vec{r} = \hat{i}(-2 + 2) - \hat{j}(-4 + 3) + \hat{k}(4 - 3) = \hat{j} + \hat{k}$
$|\vec{F} \times \vec{r}| = \sqrt{2}$
So the answer is (d) $10, \sqrt{2}$ .

Report a mistake

Vector (Cross) Product question from NEET 2022 (Phase 2)

More questions on Vector (Cross) Product