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NEET 2000 (AIPMT) · Power

Power question from NEET 2000 (AIPMT)

Q50NEET 2000 · AIPMTEasy

Power

If F⃗=(60i^+15j^−3k^)\vec{F} = \left(60\hat{i} + 15\hat{j} - 3\hat{k}\right) N andv⃗=(2i^−4j^+5k^)\vec{v} = \left(2\hat{i} - 4\hat{j} + 5\hat{k}\right) m/s, then instantaneous power is

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Answer: (b)

  1. P=F⃗⋅v⃗P = \vec{F} \cdot \vec{v}.
  2. P=(60)(2)+(15)(−4)+(−3)(5)=120−60−15=45 WP = (60)(2) + (15)(-4) + (-3)(5) = 120 - 60 - 15 = 45\text{ W}
  3. So the answer is (b) 45 watt.
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