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MHT CET 2023 (10 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2023 (10 May, Shift 1)

Q100MHT CET 2023 · 10 MAY · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

If 'I' is moment of inertia of a thin circular disc about an axis passing through the tangent of the disc and in the plane of disc. The moment of inertia of same circular disc about an axis perpendicular to plane and passing through its centre is

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Answer: (b)

Tangent in plane: $I = \frac{1}{4}MR^2 + MR^2 = \frac{5}{4}MR^2 \Rightarrow MR^2 = \frac{4I}{5}$ .
Perpendicular axis through centre: $I_c = \frac{1}{2}MR^2 = \frac{2I}{5}$
So the answer is (b) $\frac{2I}{5}$ .

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