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JEE Main 2002 (AIEEE) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from JEE Main 2002 (AIEEE)

Q110JEE Main 2002 · AIEEEEasy

Biot-Savart Law & Circular Coils

If in a circular coil AA of radius R,R, current II is flowing and in another coil BB of radius 2R2R a current 2I2I is flowing, then the ratio of the magnetic fields BAB_A and BBB_B, produced by them will be

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Answer: (a)

  1. B=μ0I2R∝IRB = \frac{\mu_0 I}{2R} \propto \frac{I}{R}
  2. BABB=I/R2I/(2R)=1\frac{B_A}{B_B} = \frac{I/R}{2I/(2R)} = 1
  3. So the answer is (a) 1.
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