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Photoelectric Effect: Einstein's Equation question from NEET 2024

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Photoelectric Effect: Einstein's Equation

If ϕ\phi is the work function of photosensitive material in eV\text{eV} and light of wavelength of numerical value λ=hce\lambda = \frac{hc}{e} metre, is incident on it with energy above its threshold value at an instant then the maximum kinetic energy of the photo-electron ejected by it at that instant (Take hh-Plank's constant, cc-velocity of light in free space) is (in SI units):

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Answer: (c)

  1. Photon energy E=hcλ=hchc/e=eE = \frac{hc}{\lambda} = \frac{hc}{hc/e} = e (in joules, i.e. 1 eV).
  2. Einstein's equation: Kmax=E−ϕK_{max} = E - \phi
  3. Kmax=e−ϕK_{max} = e - \phi (with ϕ\phi taken in the same units)
  4. So the answer is (c) e−ϕe - \phi.
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