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MHT CET 2024 (3 May, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2024 (3 May, Shift 2)

Q53MHT CET 2024 · 3 MAY · SHIFT 2Easy

Organ Pipes & Resonance Tube

If ' $l$ ' is the length of pipe, ' $r$ ' is the internal radius of the pipe and ' $v$ ' is the velocity of sound in air then fundamental frequency of open pipe is

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Answer: (a)

End correction at each open end $e = 0.6r$ ; an open pipe has two ends, so effective length $= l + 1.2r$ .
Fundamental of open pipe: $f = \frac{V}{2(l + 1.2r)}$
So the answer is (a) $\frac{V}{2(l+1.2r)}$ .

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