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MHT CET 2026 (12 May, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2026 (12 May, Shift 2)

Q14MHT CET 2026 · 12 MAY · SHIFT 2Medium

Simple Pendulum

If length of oscillating simple pendulum is made $\left(\frac{1}{3}\right)$ times at a place keeping amplitude same then its total energy will be

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Answer: (b)

$E = \frac{1}{2}m\omega^2A^2 = \frac{mgA^2}{2L}$ , so $E \propto \frac{1}{L}$ for the same $A$ .
$L \to \frac{L}{3} \Rightarrow E \to 3E$
So the answer is (b) 3 times.

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