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NEET 2004 (AIPMT) · Mass Defect & Binding Energy

Mass Defect & Binding Energy question from NEET 2004 (AIPMT)

Q27NEET 2004 · AIPMTEasy

Mass Defect & Binding Energy

If M(A; Z), Mp and Mn denote the masses of the nucleus ZAX,{}_{Z}^{A}X, proton and neutron respectively in units of u (1 u = 931.5 MeV/c2) and BE represents its bonding energy in MeV, then

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Answer: (c)

  1. Mass defect: Δm=ZMp+(A−Z)Mn−M(A,Z)=BEc2\Delta m = ZM_p + (A - Z)M_n - M(A, Z) = \dfrac{BE}{c^2}
  2. Rearranging: M(A,Z)=ZMp+(A−Z)Mn−BEc2M(A, Z) = ZM_p + (A - Z)M_n - \dfrac{BE}{c^2}
  3. So the answer is (c).
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