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JEE Main 2019 (9 Apr, Shift 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from JEE Main 2019 (9 Apr, Shift 1)

Q62JEE Main 2019 · 9 APR · SHIFT 1Medium

Angle of Contact & Capillarity

If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is:

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Answer: (d)

  1. h=2Tcos⁡θrρg∝1rh = \dfrac{2T\cos\theta}{r\rho g} \propto \dfrac{1}{r}.
  2. Mass m=πr2hρ∝rm = \pi r^2 h\rho \propto r (equivalently, weight mgmg = upward force 2πrTcos⁡θ∝r2\pi r T\cos\theta \propto r).
  3. Radius 2r⇒2r \Rightarrow mass 2M2M.
  4. So the answer is (d) 2M2M.
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