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MHT CET 2024 (16 May, Shift 1) · Mass Defect & Binding Energy

Mass Defect & Binding Energy question from MHT CET 2024 (16 May, Shift 1)

Q9MHT CET 2024 · 16 MAY · SHIFT 1Easy

Mass Defect & Binding Energy

If $\mathrm{M_O}$ is the mass of an oxygen isotope ${}_{8}\text{O}^{17}$ and $\mathrm{M_p}$ and $\mathrm{M_N}$ are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is

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Answer: (d)

${}_{8}\text{O}^{17}$ has $Z = 8$ protons and $N = 17 - 8 = 9$ neutrons.
Mass defect $\Delta m = 8M_P + 9M_N - M_O$ ; binding energy $= \Delta m\, c^2$ .
Option (d) is $(M_O - 8M_P - 9M_N)c^2$ , which has the same magnitude.
So the answer is (d).

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