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JEE Main 2022 (25 Jul, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2022 (25 Jul, Shift 1)

Q36JEE Main 2022 · 25 JUL · SHIFT 1Easy

Applications of Dimensional Analysis

If momentum [P], area [A][\mathrm{A}] and time [T][\mathrm{T}] are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is:

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Answer: (a)

  1. η=F/Adv/dx\eta = \dfrac{F/A}{dv/dx}, and velocity gradient has dimensions [T−1][T^{-1}].
  2. [η]=[F][A−1][T][\eta] = [F][A^{-1}][T], with force F=P/TF = P/T.
  3. [η]=[PT−1][A−1][T]=[PA−1T0][\eta] = [PT^{-1}][A^{-1}][T] = [PA^{-1}T^0].
  4. So the answer is (a).
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