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JEE Main 2021 (16 Mar, Shift 2) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2021 (16 Mar, Shift 2)

Q20JEE Main 2021 · 16 MAR · SHIFT 2Difficult

Gravitational Potential & Energy

If one wants to remove all the mass of the earth to infinity in order to break it up completely. The amount of energy that needs to be supplied will be x5GM2R\frac{x}{5}\frac{GM^2}{R} where x is __________ (Round off to the Nearest Integer) (M is the mass of earth, R is the radius of earth, G is the gravitational constant)

Numerical answer type. Work it out, then open the answer.

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Answer: 3

  1. Energy needed = gravitational self-energy (binding energy) of a uniform sphere.
  2. E=35GM2RE = \frac{3}{5}\frac{GM^2}{R}
  3. Compare with x5GM2R\frac{x}{5}\frac{GM^2}{R}
  4. So x=3x = 3.
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