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JEE Main 2015 (10 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2015 (10 Apr, Shift 1)

Q112JEE Main 2015 · 10 APR · SHIFT 1Difficult

Bohr Model: Orbits, Speed & Angular Momentum

If one were to apply Bohr model to a particle of mass 'm' and charge 'q' moving in a plane under the influence of a magnetic field 'B', the energy of the charged particle in the nth level will be:

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Answer: (b)

  1. qvB=mv2r⇒r=mvqBqvB = \frac{mv^2}{r} \Rightarrow r = \frac{mv}{qB}.
  2. Bohr condition: mvr=m2v2qB=nh2π⇒v2=nhqB2πm2mvr = \frac{m^2 v^2}{qB} = \frac{nh}{2\pi} \Rightarrow v^2 = \frac{nhqB}{2\pi m^2}.
  3. Energy is only kinetic: E=12mv2=n(hqB4πm)E = \frac{1}{2}mv^2 = n\left(\frac{hqB}{4\pi m}\right)
  4. So the answer is (b) n(hqB4πm)n\left(\frac{hqB}{4\pi m}\right).
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