Physics Circle home Student Login

Home›Chapters›Vectors PYQs›Vector (Cross) Product›Question 11

JEE Main 2021 (25 Feb, Shift 2) · Vector (Cross) Product

Vector (Cross) Product question from JEE Main 2021 (25 Feb, Shift 2)

Q11JEE Main 2021 · 25 FEB · SHIFT 2Easy

Vector (Cross) Product

If P⃗×Q⃗=Q⃗×P⃗\vec{P} \times \vec{Q} = \vec{Q} \times \vec{P}, the angle between P⃗\vec{P}and Q⃗\vec{Q} is θ(0∘\theta(0^\circ < θ\theta < 360∘^\circ). The value of 'θ\theta' will be ___________∘^\circ.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 180

  1. Q⃗×P⃗=−P⃗×Q⃗\vec{Q} \times \vec{P} = -\vec{P} \times \vec{Q}, so the condition gives 2P⃗×Q⃗=02\vec{P} \times \vec{Q} = 0.
  2. PQsin⁡θ=0⇒sin⁡θ=0PQ\sin\theta = 0 \Rightarrow \sin\theta = 0.
  3. In 0∘<θ<360∘0^\circ < \theta < 360^\circ the only value is θ=180∘\theta = 180^\circ.
  4. So θ=180∘\theta = 180^\circ.
Report a mistake

More questions on Vector (Cross) Product