If Δ Q is the amount of heat supplied to 'n' moles of a rigid diatomic gas at constant pressure, Δ U is the change in internal energy and Δ W is the work done then Δ W: Δ U: Δ Q is (a) 2: 5: 7 (b) 1: 4: 7 (c) 2: 3: 4 (d) 3: 5: 9

Answer: (a). Isobaric: Δ W: Δ U: Δ Q = R: Cv: Cp. Rigid diatomic: Cv = 5/2R, Cp = 7/2R. 1: 5/2: 7/2 = 2: 5: 7 So the answer is (a) 2: 5: 7.

If Δ Q is the amount of heat supplied to 'n' moles of a rigid… | MHT CET 2026 (11 Apr, Shift 2)

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Thermodynamic Processes

If $\Delta Q$ is the amount of heat supplied to 'n' moles of a rigid diatomic gas at constant pressure, $\Delta U$ is the change in internal energy and $\Delta W$ is the work done then $\Delta W : \Delta U : \Delta Q$ is

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Answer: (a)

Isobaric: $\Delta W : \Delta U : \Delta Q = R : C_v : C_p$ .
Rigid diatomic: $C_v = \dfrac{5}{2}R$ , $C_p = \dfrac{7}{2}R$ .
$1 : \dfrac{5}{2} : \dfrac{7}{2} = 2 : 5 : 7$
So the answer is (a) $2 : 5 : 7$ .

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