If radius of the ₁₃²⁷ Al nucleus is taken to be RAl, then the radius of ₅₂¹²⁵ Te nucleus is nearly (a) 3/5 RAl (b) (13/53)1/3 RAl (c) (53/13)1/3 RAl (d) 5/3 RAl

Answer: (d). R ∝ A1/3, so RTeRAl = (125/27)1/3. = 5/3 So the answer is (d) 5/3 RAl.

If radius of the ₁₃²⁷ Al nucleus is taken to be RAl, then the radius… | NEET 2015 (AIPMT, Cancelled Paper)

Q27NEET 2015 · AIPMT · CANCELLED PAPEREasy

Nucleus: Composition, Size & Nuclear Force

If radius of the ${}_{13}^{27}$ Al nucleus is taken to be RAl, then

the radius of ${}_{52}^{125}$ Te nucleus is nearly

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Answer: (d)

$R \propto A^{1/3}$ , so $\frac{R_{Te}}{R_{Al}} = \left(\frac{125}{27}\right)^{1/3}$ .
$= \frac{5}{3}$
So the answer is (d) $\frac{5}{3} R_{Al}$ .