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MHT CET 2019 (2 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2019 (2 May, Shift 1)

Q157MHT CET 2019 · 2 MAY · SHIFT 1Easy

Moment of Inertia & Radius of Gyration

If radius of the solid sphere is doubled by keeping its mass constant, the ratio of their moment of inertia about any of its diameter is

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Answer: (d)

  1. I=25MR2⇒I∝R2I = \frac{2}{5}MR^2 \Rightarrow I \propto R^2 for fixed MM.
  2. I1I2=(R2R)2=14\frac{I_1}{I_2} = \left(\frac{R}{2R}\right)^2 = \frac{1}{4}
  3. So the answer is (d) 1:41:4.
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