If temperature of gas molecules is raised from 127 to 527, the ratio of r.m.s. speed of the molecules is respectively (a) 1: 2 (b) 2: 1 (c) 1: √(2) (d) 2: √(2)

Answer: (c). T₁ = 127 + 273 = 400 K, T₂ = 527 + 273 = 800 K (v₁)/(v₂) = √((T₁)/(T₂)) = √((400)/(800)) = 1/√(2) So the answer is (c) 1: √(2).

If temperature of gas molecules is raised from 127 to 527, the ratio… | MHT CET 2023 (11 May, Shift 2)

Q35MHT CET 2023 · 11 MAY · SHIFT 2Easy

Molecular Speeds & Maxwell Distribution

If temperature of gas molecules is raised from $127^\circ\text{C}$ to $527^\circ\text{C}$ , the ratio of r.m.s. speed of the molecules is respectively

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Answer: (c)

$T_1 = 127 + 273 = 400\text{ K}$ , $T_2 = 527 + 273 = 800\text{ K}$
$\frac{v_1}{v_2} = \sqrt{\frac{T_1}{T_2}} = \sqrt{\frac{400}{800}} = \frac{1}{\sqrt{2}}$
So the answer is (c) $1 : \sqrt{2}$ .

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