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MHT CET 2026 (15 May, Shift 1) · Terminal Velocity

Terminal Velocity question from MHT CET 2026 (15 May, Shift 1)

Q6MHT CET 2026 · 15 MAY · SHIFT 1Medium

Terminal Velocity

If terminal speed of a sphere of gold (density = 19.519.5 kg/m3^{3}) is 0.20.2 m/s in viscous liquid (density = 1.51.5 kg/m3^{3} ), find the terminal speed of a sphere of silver (density = 10.510.5 kg/m3^{3}) of the same size in the same liquid.

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Answer: (c)

  1. Same size and liquid: v∝(ρ−σ)v \propto (\rho - \sigma).
  2. vsvg=10.5−1.519.5−1.5=918=12\dfrac{v_s}{v_g} = \dfrac{10.5 - 1.5}{19.5 - 1.5} = \dfrac{9}{18} = \dfrac{1}{2}
  3. vs=0.2×12=0.1v_s = 0.2 \times \frac{1}{2} = 0.1 m/s
  4. So the answer is (c) 0.10.1 m/s.
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