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JEE Main 2019 (9 Jan, Shift 1) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2019 (9 Jan, Shift 1)

Q61JEE Main 2019 · 9 JAN · SHIFT 1Medium

Angular Momentum & its Conservation

If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is:

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Answer: (c)

  1. Areal velocity dAdt=12r2ω=12rv\frac{dA}{dt}=\frac12r^2\omega=\frac12rv.
  2. L=mvr⇒rv=LmL=mvr\Rightarrow rv=\frac Lm
  3. dAdt=L2m\frac{dA}{dt}=\frac{L}{2m}
  4. So the answer is (c) L2m\frac{L}{2m}.
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