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NEET 2020 (Phase 2) · Total Internal Reflection

Total Internal Reflection question from NEET 2020 (Phase 2)

Q36NEET 2020 · PHASE 2Easy

Total Internal Reflection

If the critical angle for total internal reflection from a medium to vacuum is 45∘45^\circ, then velocity of light in the medium is,

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Answer: (c)

  1. μ=1sin⁡C=1sin⁡45∘=2\mu = \frac{1}{\sin C} = \frac{1}{\sin 45^\circ} = \sqrt{2}.
  2. v=cμ=3×1082 m/sv = \frac{c}{\mu} = \frac{3 \times 10^8}{\sqrt{2}}\text{ m/s}
  3. So the answer is (c) 32×108 m/s\frac{3}{\sqrt{2}} \times 10^8\text{ m/s}.
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