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MHT CET 2026 (18 Apr, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (18 Apr, Shift 2)

Q15MHT CET 2026 · 18 APR · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

If the difference between (n+1)th(n+1)^{th} Bohr radius and nthn^{th} Bohr radius is given by (n−1)th(n-1)^{th} Bohr radius, then the value of n is

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Answer: (a)

  1. Bohr radius rn∝n2r_n \propto n^2.
  2. (n+1)2−n2=(n−1)2⇒2n+1=n2−2n+1(n+1)^2 - n^2 = (n-1)^2 \Rightarrow 2n + 1 = n^2 - 2n + 1
  3. n2=4n⇒n=4n^2 = 4n \Rightarrow n = 4
  4. So the answer is (a) 44.
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