If the dimensions of a physical quantity are given by MaLbTc, then the physical quantity will be (a) velocity if a = 1, b = 0, c = - 1 (b) acceleration if a = 1, b = 1, c = - 2 (c) force if a = 0, b = - 1, c = - 2 (d) pressure if a = 1, b = - 1, c = - 2

Answer: (d). Velocity [M⁰LT⁻¹]: (a) wrong, needs a = 0. Acceleration [M⁰LT⁻²]: (b) wrong, needs a = 0. Force [MLT⁻²]: (c) wrong. Pressure = F/A = [ML⁻¹T⁻²]: a = 1, b = -1, c = -2. So the answer is (d).

If the dimensions of a physical quantity are given by MaLbTc, then… | NEET 2009 (AIPMT)

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Units & Dimensions

If the dimensions of a physical quantity are given by MaLbTc, then the physical quantity will be

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Answer: (d)

Velocity $[\mathrm{M^0LT^{-1}}]$ : (a) wrong, needs $a = 0$ .
Acceleration $[\mathrm{M^0LT^{-2}}]$ : (b) wrong, needs $a = 0$ .
Force $[\mathrm{MLT^{-2}}]$ : (c) wrong.
Pressure $= \frac{F}{A} = [\mathrm{ML^{-1}T^{-2}}]$ : $a = 1, b = -1, c = -2$ .
So the answer is (d).

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