If the electric flux entering and leaving an enclosed surface are φ₁ and φ₂ respectively, the electric charge inside the surface will be (a) (φ₂ - φ₁)/(ε₀) (b) (φ₁ + φ₂)/(ε₀) (c) ε₀(φ₁ - φ₂) (d) ε₀(φ₂ - φ₁)

Answer: (d). Net outward flux φnet = φleaving - φentering = φ₂ - φ₁. Gauss's law: φnet = (q)/(ε₀) ⇒ q = ε₀(φ₂ - φ₁). So the answer is (d) ε₀(φ₂ - φ₁).

If the electric flux entering and leaving an enclosed surface are φ₁… | MHT CET 2024 (4 May, Shift 2)

Q42MHT CET 2024 · 4 MAY · SHIFT 2Easy

Electric Flux & Gauss's Law

If the electric flux entering and leaving an enclosed surface are $\phi_1$ and $\phi_2$ respectively, the electric charge inside the surface will be

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Answer: (d)

Net outward flux $\phi_{net} = \phi_{leaving} - \phi_{entering} = \phi_2 - \phi_1$ .
Gauss's law: $\phi_{net} = \dfrac{q}{\varepsilon_0} \Rightarrow q = \varepsilon_0(\phi_2 - \phi_1)$ .
So the answer is (d) $\varepsilon_0(\phi_2 - \phi_1)$ .

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Electric Flux & Gauss's Law question from MHT CET 2024 (4 May, Shift 2)

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