If the electric flux entering and leaving an enclosed surface is φ₁ and φ₂ then charge enclosed in the surface is ( ε₀ = permittivity of free space) (a) (φ₂ - φ₁)/(ε₀) (b) (φ₂ + φ₁)/(ε₀) (c) (φ₁ - φ₂)/(ε₀) (d) ε₀(φ₂ - φ₁)

Answer: (d). Net outward flux = φ₂ - φ₁. φ₂ - φ₁ = (q)/(ε₀) ⇒ q = ε₀(φ₂ - φ₁) So the answer is (d).

If the electric flux entering and leaving an enclosed surface is φ₁… | MHT CET 2024 (9 May, Shift 1)

Q39MHT CET 2024 · 9 MAY · SHIFT 1Easy

Electric Flux & Gauss's Law

If the electric flux entering and leaving an enclosed surface is $\phi_1$ and $\phi_2$ then charge enclosed in the surface is ( $\varepsilon_0 =$ permittivity of free space)

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Answer: (d)

Net outward flux $= \phi_2 - \phi_1$ .
$\phi_2 - \phi_1 = \dfrac{q}{\varepsilon_0} \Rightarrow q = \varepsilon_0(\phi_2 - \phi_1)$
So the answer is (d).

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