If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe is (a) 1/3 cm (b) 2/3 cm (c) 3/2 cm (d) 0.2 cm

Answer: (b). An open pipe has two open ends, so its total end correction is 2(0.6r) = 1.2r. 1.2r = 0.8 ⇒ r = (0.8)/(1.2) = 2/3 cm So the answer is (b) 2/3 cm.

If the end correction of an open pipe is 0.8 cm, then the inner… | MHT CET 2023 (9 May, Shift 2)

Q66MHT CET 2023 · 9 MAY · SHIFT 2Easy

Organ Pipes & Resonance Tube

If the end correction of an open pipe is $0.8\text{ cm}$ , then the inner radius of that pipe is

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Answer: (b)

An open pipe has two open ends, so its total end correction is $2(0.6r) = 1.2r$ .
$1.2r = 0.8 \Rightarrow r = \frac{0.8}{1.2} = \frac{2}{3}\text{ cm}$
So the answer is (b) $\frac{2}{3}\text{ cm}$ .

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