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NEET 1989 (AIPMT) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from NEET 1989 (AIPMT)

Q80NEET 1989 · AIPMTMedium

Satellites - Orbital Velocity & Period

If the gravitational force between two objects were proportional to $1/R$ (and not as $1/R^2$ ), where $R$ is the distance between them, then a particle in a circular path (under such a force) would have its orbital speed $v$ , proportional to

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Answer: (b)

Centripetal force from the given law: $\frac{mv^2}{R} = \frac{k}{R}$ .
$mv^2 = k$ , so $v$ does not depend on $R$ .
So the answer is (b) $R^0$ .

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