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JEE Main 2022 (26 Jul, Shift 1) · Projectile Basics & Trajectory

Projectile Basics & Trajectory question from JEE Main 2022 (26 Jul, Shift 1)

Q3JEE Main 2022 · 26 JUL · SHIFT 1Medium

Projectile Basics & Trajectory

If the initial velocity in horizontal direction of a projectile is unit vector i^\hat{i} and the equation of trajectoryy=5x(1−x)y = 5x(1 - x). The yy component vector of the initial velocity is ______________ j^\hat{j}. (Take g=10 m/s2)\text{Take } g = 10\text{ m/s}^{2})

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. y=5x−5x2y = 5x - 5x^2; compare with y=xuyux−gx22ux2y = x\frac{u_y}{u_x} - \frac{gx^2}{2u_x^2}
  2. g2ux2=102(1)2=5\frac{g}{2u_x^2} = \frac{10}{2(1)^2} = 5 (consistent with ux=1u_x = 1)
  3. uyux=5⇒uy=5\frac{u_y}{u_x} = 5 \Rightarrow u_y = 5
  4. So the yy component is 5j^5\hat j m/s, answer 5.
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