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JEE Main 2005 (AIEEE) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2005 (AIEEE)

Q146JEE Main 2005 · AIEEEEasy

Matter Waves: de Broglie Wavelength

If the kinetic energy of a free electron doubles, it's deBroglie wavelength changes by the factor

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Answer: (d)

$\lambda = \dfrac{h}{\sqrt{2mK}} \Rightarrow \lambda \propto \dfrac{1}{\sqrt{K}}$ .
$K' = 2K \Rightarrow \lambda' = \dfrac{\lambda}{\sqrt{2}}$ .
So the answer is (d) $\dfrac{1}{\sqrt{2}}$ .

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