Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Matter Waves: de Broglie Wavelength›Question 6

MHT CET 2026 (18 Apr, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2026 (18 Apr, Shift 1)

Q6MHT CET 2026 · 18 APR · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

If the kinetic energy of a particle is increased to 16 times, the percentage change in the de Broglie wavelength of a particle is

Show answer and solution

Answer: (c)

  1. λ=h2mK∝1K\lambda = \dfrac{h}{\sqrt{2mK}} \propto \dfrac{1}{\sqrt{K}}.
  2. K′=16K⇒λ′=λ4K' = 16K \Rightarrow \lambda' = \dfrac{\lambda}{4}
  3. Change =λ−λ/4λ×100=75%= \dfrac{\lambda - \lambda/4}{\lambda} \times 100 = 75\% (decrease).
  4. So the answer is (c) 75%75\%.
Report a mistake

More questions on Matter Waves: de Broglie Wavelength