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NEET 1997 (AIPMT) · Simple Pendulum

Simple Pendulum question from NEET 1997 (AIPMT)

Q88NEET 1997 · AIPMTEasy

Simple Pendulum

If the length of a simple pendulum is increased by 2%2\%, then the time period

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Answer: (a)

  1. T∝l1/2⇒ΔTT=12ΔllT \propto l^{1/2} \Rightarrow \frac{\Delta T}{T} = \frac{1}{2}\frac{\Delta l}{l}
  2. ΔTT=12×2%=1%\frac{\Delta T}{T} = \frac{1}{2} \times 2\% = 1\%
  3. So the answer is (a) increases by 1%1\%.
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