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MHT CET 2025 (19 Apr, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2025 (19 Apr, Shift 2)

Q21MHT CET 2025 · 19 APR · SHIFT 2Easy

Simple Pendulum

If the length of the oscillating simple pendulum is made 13\frac{1}{3} times the original keeping amplitude same then increase in its total energy at a place will be

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Answer: (b)

  1. E=mgA22LE = \frac{mgA^2}{2L}, so for the same amplitude E∝1LE \propto \frac{1}{L}.
  2. L′=L3⇒E′=3EL' = \frac{L}{3} \Rightarrow E' = 3E
  3. Increase =E′−E=2E= E' - E = 2E, i.e. 2 times the original energy.
  4. So the answer is (b) 2 times.
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