If the magnitude of intensity of electric field at a distance ' r₁ ' on an axial line and at a distance ' r₂ ' on an equatorial line due to a given short dipole are equal, then r₁: r₂, is (a) √[3]2: 1 (b) √(2): 1 (c) 1: 2 (d) 1: √[3]2

Answer: (a). Short dipole: Eax = (2kp)/(r₁³), Eeq = (kp)/(r₂³). Equal fields: (2)/(r₁³) = (1)/(r₂³) ⇒ r₁³ = 2r₂³. r₁: r₂ = √[3]2: 1 So the answer is (a).

If the magnitude of intensity of electric field at a distance ' r₁ '… | MHT CET 2023 (13 May, Shift 1)

Q44MHT CET 2023 · 13 MAY · SHIFT 1Medium

Electric Dipole

If the magnitude of intensity of electric field at a distance ' $r_1$ ' on an axial line and at a distance ' $r_2$ ' on an equatorial line due to a given short dipole are equal, then $r_1 : r_2$ , is

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Answer: (a)

Short dipole: $E_{ax} = \frac{2kp}{r_1^3}$ , $E_{eq} = \frac{kp}{r_2^3}$ .
Equal fields: $\frac{2}{r_1^3} = \frac{1}{r_2^3} \Rightarrow r_1^3 = 2r_2^3$ .
$r_1 : r_2 = \sqrt[3]{2} : 1$
So the answer is (a).

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Electric Dipole question from MHT CET 2023 (13 May, Shift 1)

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