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JEE Main 2024 (31 Jan, Shift 1) · Errors in Measurement

Errors in Measurement question from JEE Main 2024 (31 Jan, Shift 1)

Q59JEE Main 2024 · 31 JAN · SHIFT 1Easy

Errors in Measurement

If the percentage errors in measuring the length and the diameter of a wire are $0.1\%$ each. The percentage error in measuring its resistance will be:

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Answer: (d)

$R = \frac{\rho l}{A} = \frac{4\rho l}{\pi d^2}$ , so $\frac{\Delta R}{R} = \frac{\Delta l}{l} + 2\frac{\Delta d}{d}$
$= 0.1\% + 2(0.1\%) = 0.3\%$
So the answer is (d) 0.3%.

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