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JEE Main 2022 (29 Jul, Shift 1) · P-N Junction Diode

P-N Junction Diode question from JEE Main 2022 (29 Jul, Shift 1)

Q60JEE Main 2022 · 29 JUL · SHIFT 1Easy

P-N Junction Diode

If the potential barrier across a p-n junction is 0.6 V0.6\text{ V}. Then the electric field intensity, in the depletion region having the width of 6×10−6 m6 \times 10^{-6}\text{ m}, will be __________ ×105 N/C\times 10^{5}\text{ N/C}.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. E=VdE = \dfrac{V}{d}
  2. E=0.66×10−6=1×105 N/CE = \dfrac{0.6}{6 \times 10^{-6}} = 1 \times 10^{5}\ \text{N/C}
  3. So the answer is 11 (i.e. 1×105 N/C1 \times 10^{5}\ \text{N/C}).
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