If the potential difference between points B and D is zero in the… | MHT CET 2026 (16 Apr, Shift 2)

Q3MHT CET 2026 · 16 APR · SHIFT 2Medium

Wheatstone Bridge & Metre Bridge

If the potential difference between points B and D is zero in the given circuit, the value of x is $\frac{1}{n}\ \Omega$ . The value n is

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Answer: (a)

Arm with B on left: $6 \parallel 3 = 2\ \Omega$ ; arm with D on left: $1 + 2 = 3\ \Omega$ .
Right arms: $x \parallel 1 = \dfrac{x}{x+1}$ (to B) and $x$ (to D).
Balance: $\dfrac{2}{x/(x+1)} = \dfrac{3}{x} \Rightarrow 2(x+1) = 3$
$x = \dfrac{1}{2}\ \Omega = \dfrac{1}{n} \Rightarrow n = 2$
So the answer is (a) $2$ .

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