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MHT CET 2023 (14 May, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2023 (14 May, Shift 1)

Q73MHT CET 2023 · 14 MAY · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

If the radius of the first Bohr orbit is ' $r$ ' then the de-Broglie wavelength of the electron in the $4$ th orbit will be

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Answer: (c)

$\lambda = \frac{2\pi r_n}{n}$ with $r_4 = 16r$
$\lambda = \frac{2\pi\times16r}{4} = 8\pi r$
So the answer is (c) $8\pi r$ .

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