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MHT CET 2026 (11 Apr, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2026 (11 Apr, Shift 2)

Q5MHT CET 2026 · 11 APR · SHIFT 2Easy

Electric Flux & Gauss's Law

If the radius of the spherical Gaussian surface is increased then the electric flux due to a point charge enclosed by the surface

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Answer: (b)

Gauss's law: $\phi = \dfrac{q_{enc}}{\varepsilon_0}$ depends only on the enclosed charge, not on the size of the surface.
So the answer is (b) remains unchanged.

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