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JEE Main 2013 (9 Apr, Shift 1) · Wire Combinations & Special Cases

Wire Combinations & Special Cases question from JEE Main 2013 (9 Apr, Shift 1)

Q30JEE Main 2013 · 9 APR · SHIFT 1Medium

Wire Combinations & Special Cases

If the ratio of lengths, radii and Young's moduli of steel and brass wires in the figure are a, b and c respectively, then the corresponding ratio of increase in their lengths is:

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Answer: (c)

Tension in steel (holds both masses) $= 3Mg$ ; tension in brass $= 2Mg$ .
$\Delta l = \frac{TL}{\pi r^2 Y}$ , so $\frac{\Delta l_s}{\Delta l_b} = \frac{3}{2} \cdot a \cdot \frac{1}{b^2} \cdot \frac{1}{c}$
$= \frac{3a}{2b^2c}$ , so the answer is (c).

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