If the ratio of molar heat capacities (Cp)/(Cv) = γ then the ratio of (Δ Q)/(Δ U) and (Δ Q)/(Δ W) in an isobaric process is (a) 2γ, (γ)/(2) (b) γ, (γ)/((γ - 1)) (c) (γ)/((γ - 1)) (d) (1)/(γ), (γ - 1)

Answer: (b). Isobaric: Δ Q = nCpΔ T, Δ U = nCvΔ T, Δ W = nRΔ T. (Δ Q)/(Δ U) = (Cp)/(Cv) = γ (Δ Q)/(Δ W) = (Cp)/(Cp - Cv) = (γ)/(γ - 1) So the answer is (b).

If the ratio of molar heat capacities (Cp)/(Cv) = γ then the ratio of… | MHT CET 2026 (14 May, Shift 2)

Q17MHT CET 2026 · 14 MAY · SHIFT 2Medium

Thermodynamic Processes

If the ratio of molar heat capacities $\frac{C_p}{C_v} = \gamma$ then the ratio of $\frac{\Delta Q}{\Delta U}$ and $\frac{\Delta Q}{\Delta W}$ in an isobaric process is

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Answer: (b)

Isobaric: $\Delta Q = nC_p\Delta T$ , $\Delta U = nC_v\Delta T$ , $\Delta W = nR\Delta T$ .
$\dfrac{\Delta Q}{\Delta U} = \dfrac{C_p}{C_v} = \gamma$
$\dfrac{\Delta Q}{\Delta W} = \dfrac{C_p}{C_p - C_v} = \dfrac{\gamma}{\gamma - 1}$
So the answer is (b).

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Thermodynamic Processes question from MHT CET 2026 (14 May, Shift 2)

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