If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of a mass of gas, when the volume changes from V to 2V at constant pressure P is (a) (R)/((γ - 1)) (b) PV (c) (PV)/((γ - 1)) (d) (γ PV)/((γ - 1))

Answer: (c). Δ U = nCvΔ T = (nRΔ T)/(γ - 1) At constant P: nRΔ T = PΔ V = PV. So the answer is (c) (PV)/(γ - 1).

If the ratio of specific heat of a gas at constant pressure to that… | NEET 1998 (AIPMT)

Q249NEET 1998 · AIPMTMedium

Thermodynamic Processes

If the ratio of specific heat of a gas at constant pressure to that at constant volume is $\gamma$ , the change in internal energy of a mass of gas, when the volume changes from $V$ to $2V$ at constant pressure $P$ is

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Answer: (c)

$\Delta U = nC_v\Delta T = \frac{nR\Delta T}{\gamma - 1}$
At constant $P$ : $nR\Delta T = P\Delta V = PV$ .
So the answer is (c) $\frac{PV}{\gamma - 1}$ .

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